Evaluate a polynomial using a given quadratic equation
Look for the expression already fixed by the equation
A given equation often fixes a combination of terms even when the variable itself has more than one possible value. Rewrite the target expression in terms of that combination before solving for the variable.
Problem
Given x2−x−1=0, find C=x4−2x3+x2.
Answer
C=1.
The same value is obtained for either root of the given equation.
Step-by-step solution
1. Read the useful relation
The given equation implies x2−x=1.
2. Rewrite the target as a square
Factor out x2 and recognize the remaining perfect square:
C=x2(x2−2x+1)=x2(x−1)2=(x2−x)2.
3. Substitute the known combination
Now C=12=1. There is no need to calculate the individual roots of the quadratic.